11x^2+40x-139=0

Solution for 11x^2+40x-139=0 equation:

11x^2+40x-139=0

a = 11; b = 40; c = -139;
Δ = b2-4ac
Δ = 402-4·11·(-139)
Δ = 7716
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7716}=\sqrt{4*1929}=\sqrt{4}*\sqrt{1929}=2\sqrt{1929}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-2\sqrt{1929}}{2*11}=\frac{-40-2\sqrt{1929}}{22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+2\sqrt{1929}}{2*11}=\frac{-40+2\sqrt{1929}}{22}
$